X2 + 2x – 12 < 0

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Emalina 8 months 2020-10-21T05:24:15+07:00 1 Answer 165 views 0

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    2020-12-05T11:44:24+07:00

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    (x+1)^2 -13<0
    (x+1)^2 <13
    \frac{1}{13}(x+1)^2 <1
    (x+1)^2 <13
    |x+1|<\sqrt{13}
    -\sqrt{13}<x+1<\sqrt{13}

    -1-\sqrt{13}<x<\sqrt{13}-1

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