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X2 + 2x – 12 < 0

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Emalina 3 years 2020-10-21T05:24:15+07:00 2020-10-21T05:24:15+07:00 1 Answer 2316 views

Riad Taufik Lazwardi excellent · Answer 1 · 2020-12-05T11:44:24+07:00

$(x+1)^2 -13<0$
$(x+1)^2 <13$
$\frac{1}{13}(x+1)^2 <1$
$(x+1)^2 <13$
$|x+1|<\sqrt{13}$
$-\sqrt{13}<x+1<\sqrt{13}$

$-1-\sqrt{13}<x<\sqrt{13}-1$