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Dalam soal-soal 1-16, sederhanakan sebanyak mungkin. Pastikan untuk menghilangkan semua tanda kurung dan menyederhanakan semua pecahan.4-2(8-11)+64-2(8-11)+6=4-2(-3)+6 =4+6+6=162. 3[2-4(7-12)]3[2-4(7-12)]=3[2-4(-5)]=3[2+20]=3[22]=663. -4[5(-3+12-4)+2(13-7)]-4[5(-3+12-4)+2(13-7)]=-4[5(5)+2(6)]=-4[25+12]=-4[37]=-1484. 5[-1(7+12-16)+4]+25[-1(7+12-16)+4]+2=5[-1(3)+4]+2=5[1]+2=7[latexpage]5. $\frac{5}{7}-\frac{1}{13}=\frac{65-7}{91}=\frac{58}{91}$6.\frac{3}{4-7}+\frac{3}{21}-\frac{1}{6}=\frac{3}{4-7}+\frac{3}{21}-\frac{1}{6}=\frac{3}{-3}+\frac{1}{7}-\frac{1}{6}=-1+\frac{1}{7}-\frac{1}{6}=\frac{-42}{42}+\frac{6}{42}-\frac{7}{42}=\frac{-43}{42} 

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[latexpage] Berikut ini beberapa jawaban (disertai langkah-langkahnya) dari soal-soal subbab 0.1: 9. $latex \left \frac{14}{21}(\frac{2}{5-\frac{1}{3}})^2 &= \frac{14}{21}(\frac{2}{\frac{14}{3}})^2 &= \frac{14}{21}(\frac{6}{14})^2 &= \frac{14}{21}(\frac{3}{7})^2 &= \frac{2}{3}(\frac{9}{49}) &= \frac{6}{49} \right$ 14. $latex 2 + \frac{3}{1+\frac{5}{2}} &= 2 + \frac{3}{\frac ...

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