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Carilah jawaban dari masalah!1.$\int (x-2)^5 dx =$[latexpage]Misal $u=x-2 \Rightarrow \frac{du}{dx}=1\Rightarrow dx=du$$\int (x-2)^5 dx = \int u^5 du = \frac{1}{6}u^6+C = \frac{1}{6}(x-2)^6+C$2.$\int (3x)^{\frac{1}{2}} dx =\frac{1}{2}(3x)^{-\frac{1}{2}}+C$5. $\int \frac{1}{x^2+4} dx = \int \frac{1}{x^2+2^2} dx=\frac{1}{2}tan^{-1}(\frac{x}{2})+C$8. $ \int \frac{2t^2}{2t^2+1}=$Catatan :$\frac{x}{x+1}=1-\frac{1}{x+1}$Proses :$ \int \frac{2t^2}{2t^2+1}=\int 1- \frac{1}{2t^2+1}= ...

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