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Bentuk Tak Tentu Lain

 

\lim_{x \rightarrow 0} \frac{sin x}{x} = \frac{0}{0}, maka

\lim_{x \rightarrow 0} \frac{sin x}{x} =\lim_{x \rightarrow 0} \frac{sin' x}{x'}= \lim_{x \rightarrow 0} \frac{cos x}{1}= 1

 

Secara umum, jika kita memperoleh bentuk \frac{0}{0}, maka kita bisa menggunakan teorema L’hopital berikut :

 

Andaikan \lim_{x \rightarrow a} f(x)=\lim_{x \rightarrow a} g(x)=0. Jika \lim_{x \rightarrow a} \frac{f'(x)}{g'(x)} ada, makalatex \lim_{x \rightarrow a} \frac{f(x)}{g(x)}=\lim_{x \rightarrow a} \frac{f'(x)}{g'(x)}$

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